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【优技教育】Oracle 19c OCP 082题库(Q 18题)- 2024年修正版
考试科目:1Z0-082
考试题量:90
通过分数:60%
考试时间:150min
本文为(CUUG 原创)整理并解析,转发请注明出处,禁止抄袭及未经注明出处的转载。
原文地址:http://www.cuug.com.cn/ocp/082kaoshitiku/38219540954.html
第18题:
Q 18、
Choose the best answer.
Examine the description of the EMPLOYEES table:
Name Null? Type
-------------------------------------------------------------
EMPLOYEE_ID NOT NULL NUMBER(4)
EMPLOYEE_NAME NOT NULL VARCHAR2 (100)
SALARY NOT NULL NUMBER(6,2) .
DEPARTMENT_ID NOT NULL NUMBER(4)
Which statement will fail?
A) SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90
HAVING COUNT(*) >= 3
GROUP BY department_id;
B) SELECT department_id, COUNT (*)
FROM employees
WHERE department_id <> 90
AND COUNT(*) >= 3
GROUP BY department_id;
C) SELECT department_id, COUNT (*)
FROM employees
WHERE department_id < 90
GROUP BY department_id
HAVING COUNT(*) >= 3;
D) SELECT department_id, COUNT (*)
FROM employees
HAVING department_id < 90
AND COUNT(*) >= 3
GROUP BY department_id;
Answer:B
(解析:D 答案是出人意料可以执行成功,原因是 having 放在了前面,它是 having 语句中的 and 条件,所以允许用到分组函数。)
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